A wire having a mass per unit length of 0.600 g/cm carries a 1.90 A current horizontally to the south.

(a) What is the direction of the minimum magnetic field needed to lift this wire vertically upward?

(b) What is the magnitude of the minimum magnetic field needed to lift this wire vertically upward?

a) the direction of the magnetic field is east.

b) The magnitude = 0.310 T

Explanation:

Step 1: Data given

Mass per unit length = 0.600 g/cm

current = 1.90 horizontally to the south

Step 2:

The force of gravity = magnetic force

m*g = i*L*B

m/L * g = i*B

B = ((m/L)*g) /i

⇒ with m/L = the mass per length unit = 0.600 g/cm = 0.0600 kg /m

⇒ g = 9.81 m/s²

⇒ i = the current = 1.90 A

B = (0.0600 * 9.81) / 1.90

B = 0.310 T

According to the right hand rule, the direction of the magnetic field is east.

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation: