The rate constant for this second‑order reaction is 0.670 M − 1 ⋅ s − 1 at 300 ∘ C. A ⟶ products How long, in seconds, would it take for the concentration of A to decrease from 0.690 M to 0.360 M?

t = 1.983 s

Explanation:

∴ α: order = 2

∴ K: rate constant = 0.670/M.sT = 300°C

⇒ - δCA/δt = (0.670/M.s)(CA²)

⇒ - ∫δCA/CA² = (0.670)∫δt

⇒ [ 1/CA - 1/CAo ] = 0.670*t

∴ CA = 0.360 M

∴ CAo = 0.690 M

⇒ [ 1/0.360 - 1/0.690 ] = 0.670*t

⇒ [ 1.3285/M ] = (0.670/M.s)*t

⇒ t = 1.983 s

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the atomic number of carbon is six, which means that a carbon atom has six protons. carbon has three naturally occurring isotopes: carbon-12, carbon-13, and carbon-14. which of these statements are true about carbon and its isotopes? select all that appl