A chemist adds 150.0mL of a 0.12/molL aluminum sulfate Al2SO43 solution to a reaction flask. Calculate the mass in grams of aluminum sulfate the chemist has added to the flask. Round your answer to 2 significant digits.

The mass of aluminium sulfate is 6.20 grams

Explanation:

Step 1: data given

Volume Al2(SO4)3 = 150.0 mL = 0.150 L

Molarity = 0.12 mol/L

Molar mass Al2(SO4)3 = 342.15 g/mol

Step 2: Calculate moles Al2(SO4)3

Moles Al2(SO4)3 = molarity * volume

Moles Al2(SO4)3 = 0.12 M * 0.150 L

Moles Al2(SO4)3 = 0.018 moles

Step 3: Calculate mass Al2(SO4)3

Mass Al2(SO4)3 = moles * molar mass

Mass Al2(SO4)3 = 0.018 moles * 342.15 g/mol

Mass Al2(SO4)3 = 6.16 grams ≈ 6.20 grams

The mass of aluminium sulfate is 6.20 grams

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