5.36 litars of nitrogen gas are at :25°C and 733 mm Hg
What would be the volume at 129 86 and 1.5 atm

4.6L

Explanation:

Use the equation (P1*V1)/(T1)=(P2*V2)/(T2)

P= pressure

V= volume

T= temperature in kelvins (remember K= C + 273)

Convert atm to mmHg or vise versa

1.5atm*(760mmhg/1atm)= 1140mmHg

(733mmHg * 5.36L)/(298K)=(1140mmHg * V)/(402K)

V= 4.6 or 4.65L (depending on sig figs)

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