A 6.55 g sample of aniline (C_{6}H_{5}H_{2}, molar mass = 93.13 g/mol) was combusted in a bomb calorimeter. If the temperature rose by 32.9°C, use the information below to determine the heat capacity of the calorimeter.

Heat Capacity of calorimeter is 6.842 kJ/°C

Explanation:

4 C6H5NH2(l) + 35 O2(g) → 24 CO2(g) + 14 H2O(g) + 4 NO2(g)

ΔH°rxn = -1.28 x 10⁴ kJ

4 moles of aniline gives 12800 kJ of heat,

1 mole of aniline will give 12800/4 kJ amount of heat = 3200 kJ

ΔH°rxn for 1 mole of aniline = -3200 kJ

1 mole of aniline weighs 93.13 g/mol

6.55 g of aniline has 6.55/93.13 moles = 0.0703 moles

And this would give off 0.0703 × 3200J amount of heat off

0.0703 × 3200 = 225.1 kJ.

Heat lost by aniline = Heat gained by calorimeter,

Heat lost by aniline = 225.1 kJ

Heat gained by calorimeter = C ΔT = C (32.9)

225.1 = C (32.9)

C = 6.842 kJ/°C

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.

here is table 2-2:

country

percent of eligible voters that voted

rank

united states

44.9%

138

canada

60.1%

107

costa rica

84.6%

14

hungary

66.9%

82

japan

57.0%

118

egypt

27.7%

159

south africa

85.5%

10

ans is no, the data set cannot be plotted as a single circle graph