Find the final temperature of the mixture, if two cup of water having masses of
150g and 250g and temperatures T1= 30 °C and T2=75 °C (respectively) are mixed
in an isolated system in which there is no heat lost.

Please help!!

The answer to your question is  Te= 58.13°C

Explanation:

Data

m1 = 150g   t1 = 30°C

m2 = 250g  t2 = 75°C

Te = final temperature

Equation

                    m(Te - T1) = -m(Te - T2)

Substitution

                    150(Te - 30) = -250(Te - 75)

Expand

                    150Te - 4500 = -250Te + 18750

Solve for Te

                    150Te + 250Te = 18750 + 4500

                                  400Te = 23250

                                         Te = 23250/400

                                         Te= 58.13°C

14 days is the half-life of phosphorus-32

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