The value of Keq for the following reaction is 0.25: SO2 (g) + NO2 (g) É SO3 (g) + NO (g) What is the value of Keq at the same temperature for the reaction below ? 2SO2 (g) + 2NO2 (g) É 2SO3 (g) + 2NO (g)

0.0625

Explanation:

The expression of the first reaction;

SO2 (g) + NO2 (g) --> SO3 (g) + NO (g)

Keq = [SO3] [NO] / ([SO2] [NO2])

The expression of the second reaction;

2SO2 (g) + 2NO2 (g) --> 2SO3 (g) + 2NO (g)

Keq = [SO3]² [NO]² / ([SO2]² [NO2]²)

Keq (Second) = Keq(first)²

Keq (Second) = 0.25² = 0.0625

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.