For an enzymatically catalyzed reaction in which the measured values for KM and Vmax are, respectively, 10.0 mM and 0.172 mM min-1, what is the value of the turnover number? The concentration of enzyme used in the reaction is 10.0 μM.

17.2 minutes is the value of the turnover number.

Explanation:

Using Michaelis-Menten equation:

Where  :

= max rate velocity

[S] = substrate concentration

= Michaelis-Menten constant

V = reaction rate

= catalytic rate constant

= initial enzyme concentration

We have :

is the rate is obtained when all enzyme is bonded to the substrate. is termed as the turnover number.

17.2 minutes is the value of the turnover number.

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

lol idk man i guess u gotta ask bill nye the science guy