In a unimolecular reaction with twice as much starting material as product at equilibrium, what is the value of Keq? Is ΔG o positive or negative? Enter Keq as a decimal. Be sure to answer all parts.

Answer : The value of is, 0.5 and = positive.

Explanation :

The unimolecular reaction is:

In unimolecular reaction, the starting material is 2 times to the product.

     .........(1)

As we know that:

    ...........(2)

Now substitute equation 1 in 2, we get:

Now we have to calculate the value of at 298 K.

where,

= standard Gibbs free energy = ?

R = gas constant = 8.314 J/mol.K

T = temperature = 298 K

= equilibrium constant = 0.5

Now put all the given values on the above formula, we get:

Thus, the value of at 298 K is, 1717.32 J/mol

As we know that:

= +ve, reaction is non spontaneous

= -ve, reaction is spontaneous

= 0, reaction is in equilibrium

Thus, the = +ve. So, the reaction is non spontaneous.

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.