A 5.95-g sample of AgNO3 is reacted with BaCl2 according to the equation to give 4.07 g of AgCl. What is the percent yield of AgCl?

The % yield of AgCl is 81.1 %

Explanation:

Step 1: Data given

Mass of AgNO3 = 5.95 grams

Molar mass AgNO3 = 169.87 g/mol

Molar mass BaCl2 = 208.23 g/mol

Mass of AgCl = 4.07 grams

Molar mass of AgCl = 143.32 g/mol

Step 2: The balanced equation

2AgNO3 + BaCl2 → 2AgCl + Ba(NO3)2

Step 3: Calculate moles AgNO3

Moles AgNO3 = mass AgNO3 / molar mass AgNO3

Moles AgNO3 = 5.95 grams / 169.87 g/mol

Moles AgNO3 = 0.0350 moles

Step 4: Calculate moles AgCl

For 2 moles AgNO3  we need 1 mol BaCl2 to produce 2 moles AgCl and 1 mol Ba(NO3)2

For 0.0350 moles AgNO3 we'll have 0.0350 moles AgCl

Step 5: Calculate mass AgCl

Mass AgCl = moles AgCl * moles AgCl

Mass AgCl = 0.0350 moles * 143.32 g/mol

Mass AgCl = 5.016 grams

Step 6: Calculate % yield AgCl

% AgCl = (4.07 grams / 5.016 grams)*100 %

% AgCl = 81.1 %

The % yield of AgCl is 81.1 %

The percentage yield of AgCl is 81.1%

The balanced equation for the reaction is given below:

Next, we shall determine the mass of AgNO₃ that reacted and the mass of AgCl produced from the balanced equation.

Molar mass of AgNO₃ = 108 + 14 + (3×16)

= 108 + 14 + 48

= 170 g/mol

Mass of AgNO₃ from the balanced equation = 2 × 170 = 340 g

Molar mass of AgCl = 108 + 35.5

= 143.5 g/mol

Mass of AgCl from the balanced equation = 2 × 143.5 = 287 g

Thus,

From the balanced equation above,

340 g of AgNO₃ reacted to produce 287 g of AgCl.

Next, we shall determine the theoretical yield of AgCl obtained by the reaction of 5.95 g of AgNO₃

This can be obtained as follow:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 287 g of AgCl.

Therefore,

5.95 g of AgNO₃ will react to produce = = 5.02 g of AgCl.

Thus, the theoretical yield of AgCl is 5.02 g

Finally, we shall determine the percentage yield of AgCl. This is illustrated below:

Actual yield AgCl = 4.07 g

Theoretical yield of AgCl = 5.02 g

Therefore, the percentage yield of AgCl is 81.1%

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the volume of fluid displaced would equal the volume of the gas. use a gas syringe - this is a laboratory instrument that can be used to withdraw a certain volume of gas from a closed system or to measure the volume of gas from a chemical reaction.