If 32.146g of MgSO4 is added to enough water to make 100.00mL solution, what is the molarity of MgSOA? noles solute Liters of solution
O 2.6706 M
O 3.7445M
O 0.037445
O 0.0026706 M
O 3869.4 M

Molar concentration is a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of the amount of substance per unit volume of solution.

The closest answer to this question is 2.68 M.

All the data are given in the question and these data is as follows:-

We have to find the molarity, so the formula we are gonna use is:-

The molar mass of

After calculation, the number of moles is equal to:-  

To find the molarity,    

Hence the closest option is A.

For more information, refer to the link:-

link

The answer to your question is 2.68 M

Explanation:

Data

mass of MgSO₄ = 32.146 g

volume of water = 100 ml

Molarity = ?

Formula

Molarity = moles / volume

Process

1.- Calculate the molar mass of MgSO₄

MgSO₄ = 24 + 32 + (16 x 4) = 120 g

2.- Calculate the number of moles of MgSO₄

                     120 g 1 mol

                    32.146 g x

                     x = (32.146 x 1) / 120

                     x = 0.268 moles

3.- Calculate molarity

Molarity = 0.268 / 0.1

Molarity = 2.68

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.