How much heat must be transferred to 100.0g of water to change its temperature by 35° C?

14700J

Explanation:

From the question given, the following were obtained:

M = 100g

ΔT = 35° C

C = 4.2J/g °C

Q=?

The heat transferred can calculated for by using the following equation

Q = MCΔT

Q = 100 x 4.2 x 35

Q= 14700J

gold is my favorite solid.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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