For the process 2SO2(g) + O2(g) Right arrow. 2SO3(g), Delta. S = –187.9 J/K and Delta. H = –198.4 kJ at 297.0 K are known. What is the entropy of this reaction? Use Delta. G = Delta. H – TDelta. S.

The question ought to be 'what is the change in free energy of the reaction' since the entropy was already given in the question and the formula for obtaining the free energy was specified.

-142.19KJ

Explanation:

From ∆G = ∆H - T∆S

∆H= -198KJ or -198000KJ

∆S= -187.9 JK-1

T= 297.0K

∆G= -198000-[297.0×(-187.9)]

∆G= -198000+55806.3

= -142193.7

=-142.19KJ