On a mission to a newly discovered planet, an astronaut finds chlorine abundances of 13.85 % for 35Cl and 86.15 % for 37Cl. What is the atomic mass of chlorine for this location? The mass of 35Cl is 34.9700 amu . The mass of 37Cl is 36.9700 amu .

36.693

Explanation:

From the question given, the following were obtained:

Let 35Cl be isotope A and 37Cl be isotope

For isotope A (35Cl),

Mass number = 34.9700

Abundance = 13.85 %

For isotope B (37Cl),

Mass number = 36.9700

Abundance = 86.15 %

Atomic mass =

[( Mass of AxAbundance A)/100] + [(Mass of BxAbundance B)/100]

[(34.97x13.85)/100] + [(36.97x86.15)/100]

= 36.693

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa