Gaseous neon has a density of 0.900 g/L at standard conditions. How many neon atoms are in 1.00 L of neon gas at standard conditions?

1.348 ×10^23 atoms

Explanation:

Given that volume = 1.00L

At standard condition, the volume of a gas is 22.4L/mol (at S.T.P)

Volume = mole /volume at STP

1 = mole/22.4

Mole= 22.4mol.

Also

Mole = number of atoms /Avogradro constant

Where avogrado's constant = 6.02×10²³

22.4 = number of atoms/6.02×10²³

Number of atoms = 1.348×10^25atoms

state the principle of separating two immiscible liquids by separating funnel. describe an activity with diagram to separate a mixture of water and kerosene oil. answer: immiscible layers separate out in layers depending on their densities in separating funne

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