If Gregory starts with 2.5 grams of CuO, how many grams of N2 can he theoretically form?

                      0.2934 g of N₂

Explanation:

                    The balance chemical equation for given reaction is as follow;

                              2 NH₃ + 3 CuO → 3 Cu + N₂ + 3 H₂O

Step 1: Calculate Moles of CuO as;

                Moles  =  Mass / M.Mass

                Moles  =  2.5 g / 79.54 g/mol

                Moles  =  0.0314 moles of CuO

Step 2: Find out moles of N₂ as;

According to equation,

                      3 moles of CuO produced  =  1 mole of N₂

So,

                0.0314 moles of CuO will produce  = X moles of N₂

Solving for X,

                       X =  0.0314 mol × 1 mol / 3 mol

                      X =  0.0104 moles of N₂

Step 3: Calculate Mass of N₂ as;

                    Mass  =  Moles × M.Mass

                    Mass  =  0.0104 mol × 28.01 g/mol

                    Mass  = 0.2934 g of N₂