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Chemistry, 19.02.2020 02:23 Javanese5987
From the following enthalpies of reaction,
4 HCl (g) + O2 (g) → 2 H2O (l) + 2 Cl2 (g) ∆H = -202.4 kJ/mol 1/2 H2 (g) + ½ F2 (g) → HF (l) ∆H = -600.0 kJ/mol H2 (g) + ½ O2 (g) → H2O (l) ∆H = -285.8 kJ/mol
Calculate ∆Hrxn for 2 HCl (g) + F2 (g) → 2 HF (l) + Cl2 (g) Just input a number.
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You know the right answer?
From the following enthalpies of reaction,
4 HCl (g) + O2 (g) → 2 H2O (l) + 2 Cl2 (g) ∆H = -2...
4 HCl (g) + O2 (g) → 2 H2O (l) + 2 Cl2 (g) ∆H = -2...
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