Naphthalene has a molal freezing point constant of 6.9 c/m and a normal freezing point of 80.2 c. Calculate the freezing point of a solution prepared by dissolving 0.0113 mol biphenyl (a molecular solid) in 190.5 g of naphthalene

The freezing point of a solution is 79.8°C

Explanation:

This is about freezing point depression:

Freezing point of pure solvent (T° F pure solvent) → 80.2°C

Freezing point of solution ( T° F solution)

The formula is → T°F pure solvent - T° F solution = Kf . m

Let's determine m (molality) with data given (mol/kg)

We convert the mass of solvent (naphthalene) from g to kg

190.5 g . 1kg/1000 g = 0.1905 kg

molality = 0.0113 mol / 0.1905 kg = 0.059 m . We put the data in the formula.

80.2°C - T° F solution = 6.9°C/m . 0.059m

T°F solution = - (6.9°C/m . 0.059m  -  80.2°C)

T°F solution = 79.8°C

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.

it is a good conductor

explanation: