There is 60.0% oxygen by mass in a certain compound of sulfur and oxygen. Percent by mass is a ratio of the number of grams of a particular component to 100 g of the total sample. How many grams of sulfur are in a 14.6 g sample of the compound?

The mass of sulfur in the given amount of sample is 5.84 grams.

Explanation:

We are given:

60.0% oxygen by mass in a compound

This means that 60 grams of oxygen are present in 100 grams of a compound

So, mass of sulfur in the compound is 40 grams

Given mass of the compound = 14.6 grams

Applying unitary method:

In 100 grams of a compound, the mass of sulfur is 40 grams

So, in 14.6 grams of a compound , the mass of sulfur will be =

Hence, the mass of sulfur in the given amount of sample is 5.84 grams.

lithosphere and asthenosphere

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied