What is the volume of a solution that has a molarity of 0.600M and contains 4.50 grams of NH4OH?

The volume is 214, 3 ml

Explanation:

We calculate the weight of 1 mol of  NH4OH:

Weight  1 mol NH4OH=  Weight N + (Weight H) * 5 + Weight 0

Weight  1 mol NH4OH= 14g + 1 g* 5 + 16g = 35 g/mol

1 mol NH4OH35 g

0,6mol NH4OHX=(0,6mol NH4OHx 35 g)/1 mol NH4OH= 21 g

We have 0,6 mol in 1000ml of solution (0,600 M)

21g NH4OH1000ml

4,50 g NH4OHx= (4,50 g NH4OH  x 1000ml)/21 g NH4OH= 214, 2857143 ml