If light at 193 nm from an argon–fluoride laser is incident on a gold metal surface, electrons with kinetic energy of 1.80  10–19 J are produced. What is the work function of gold in kJ/mol? What is the minimum wavelength of light in nm required to produce photoelectrons from gold (zero kinetic energy)?

work function= 8.2×10-19J

Minimum wavelength of light required= 2.4×10-7m

Explanation:

The wavelength of incident light was given as 193nm. We have to convert this to meters and have 193×10-9m. Then we use it to find the energy of incident photon E. When E is found we now apply Einstein photoelectric equation to obtain the work function Wo since the kinetic energy of photoelectrons is known as 1.8×10-19J.

From this work function. We can obtain the minimum wavelength of light required. All these steps are shown in the image attached.

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong

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