A chemist determines by measurements that moles of fluorine gas participate in a chemical reaction. Calculate the mass of fluorine gas that participates. Be sure your answer has the correct number of significant digits.

The question is incomplete, here is the complete question:

A chemist determines by measurements that 0.0850 moles of fluorine gas participate in a chemical reaction. Calculate the mass of fluorine gas that participates. Be sure your answer has the correct number of significant digits.

The mass of fluorine gas that is precipitated is 3.23 grams

Explanation:

To calculate the number of moles, we use the equation:

We are given:

Moles of fluorine gas = 0.0850 moles

Molar mass of fluorine gas = 38.0 g/mol

Putting values in above equation, we get:

Hence, the mass of fluorine gas that is precipitated is 3.23 grams

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