Aqueous hydrochloric acid (HCI) will react with sodium hydroxide (NaOH) to produce and liquid water (H2O). Suppose 1.1 grams of hydrochloric acid is mixed with 0.420 grams of sodium hydroxide. Calculate the maximum mass of sodium chloride that could be produced by the chemical reaction. Round your answer to 3 significant digits

The maximum mass of NaCl is 0.54 g.

Explanation:

The reaction can be represented with the following equation:

                    HCl + NaOH ---->  NaCl + H2O

According  to  the  equation,  equal  amounts  of  chemical  agents  and  resultant  products  (in moles) participate in this reaction.

The amount of hydrochloric acid is as follows:

                                     = 1.1 / (1 + 35.46)

                             = 0.030 moles.

where m is the mass,

           A is the atomic mass of an element.

The amount of sodium hydroxide is as follows:

                                        = 0.420 / (23 + 16 + 1)

                                        = 0.0105 moles.

Since  the  amount  of  sodium  hydroxide  exceeds  the  amount  of  hydrochloric  acid,  the maximum amount of each substance participating in the reaction is v = = 0.030 moles.

Therefore, the maximum amount of water that can be produced is as follows:

                                        = (2 1 + 16) 0.030 = 0.54 g.

          The maximum mass of NaCl is 0.54 g.