What molal concentration of KOH(aq) has the same freezing point as 0.4 m Al(NO3)3(aq)? Enter only a numerical answer. Do not include units.

The molal concentration of KOH (aq) is 0.8

Explanation:

Depression in freezing point:

where,

= freezing point of solution

= freezing point of solvent

= freezing point constant

m = molality

i = Van't Hoff factor = number of ions produced on dissociation

For i =2 as

For i =4 as

Now put all the given values in the above formula, we get:

For 0.4

For KOH

Thus molal concentration of KOH (aq) is 0.8