What mass of Al is required to completely react with 25.0 g MnO2? What mass of is required to completely react with 25.0 ? 10.3 g Al 12.4 g Al 5.82 g Al 7.76 g Al

10.3 g of Al is required to completely react with 25.0 g

Explanation:

The balanced chemical equation for the reaction is:

To find the moles we use the formula=

moles of

According to stoichiometry:

3 moles of reacts with = 4 moles of aluminium

0.287 moles of reacts with = moles of aluminium

Mass of aluminium =

Thus 10.3 g of Al is required to completely react with 25.0 g

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa