Calculate the concentration of CO2 in water at 25 degrees Celsius when the pressure of CO2 over the solution is 4.5 atm. At 25 degrees Celsius, the Henry's law constant for CO2 in water is 3.1 * 10^-2 mol/L*atm.

? M

Answer : The concentration of is, 0.12 M

Explanation :

Using Henry's law :

where,

= concentration of = ?

= partial pressure of = 4.5 atm

= Henry's law constant  =

Now put all the given values in the above formula, we get:

Thus, the concentration of is, 0.12 M

your parents i think this could be it

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"