Glucose, C6 H12O6 , is used as an energy source by the human body. The overall reaction in the body is described by the equation C6H12O6(aq)+ 6O2(g) ⟶ 6CO2(g)+ 6H2O.
1) Calculate the number of grams of oxygen required to convert 38.0 g of glucose to CO2 and H2O.
2) Also compute the number of grams of CO2 produced.

1. 40.5 grams of O₂ are needed in the reaction.

2. 55.4 grams of CO₂ are produced

Explanation:

C₆H₁₂O₆(aq)+ 6O₂(g) ⟶ 6CO₂(g)+ 6H₂O

1 mol of glucose reacts with 6 moles of oxygen to produce 6 moles of carbon dioxide and 6 moles of water.

Ratio in the reactants is 1:6. Let's convert the mass of glucose to moles.

38 g / 180 g/mol = 0.211 moles

1 mol of glucose needs 6 moles of O₂ to react

Then, 0.211 moles would need (0.211 . 6) /1 = 1.26 moles

Let's convert the moles to mass of O₂

1.26 mol . 32 g / 1mol = 40.5 g

Ratio between oxygen and carbon dioxide is 6:6. Therefore is the same to say 1:1 → 6 moles of O₂ produce 6 moles of CO₂

Then, 1.26 moles of O₂ must produce 1.26 moles of CO₂

Let's convert the moles to mass → 1.26 mol . 44 g / 1mol = 55.4 g

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