If the heat released during condensation goes only to warming the iron block, what is the final temperature (in ∘C∘C) of the iron block? (Assume a constant enthalpy of vaporization for water of 44.0 kJ/molkJ/mol.)

91 °C.

Explanation:

q = n * Delta Hvap

Where,

n = number of moles

= 0.95/18

= 0.053 mol.

q = 0.053 * -44

= -2.32 kJ

q = -qw

= -(-2.32)

= 2.32 kJ.

q = m * C * Delta T

Delta T = Temp.f - Temp.i

Temp.f = q/(m * C) + Temp.i

= 2320/(75 * 0.449) + 22

= 91 °C.

wher is the rest of the question