How can you make a 250 ml 0.5 m solution of NaCl
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Add water to 29.22 grams of salt until you get 1 liter of volume, stir it until the salt completely dissolves and mixes and voila! you will have a 0.5 M NaCl solution.

:)

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2