An alloy contains 56 g of pure silver and 22 g of copper. what is the percentage of silver in the alloy.

Find the molar mass of both of them so Cu is 63.5g/mol and Ag is 107.8g/mol and then divide the mass in grams for each by the molar mass of each to get the number of moles so 56g/107.8g=.52moles and 22g/63.5g=.35moles. Add the number of moles together and divide the number of moles of silver by that sum so .52mol+.35mol/.35=2.4*100%.

668900 atoms in total

10.063g / 10.00 ml = 1.0063 g/ml which rounds off to 4 sig figs as: 1.006 g/ml