The position of equilibrium would not be appreciably affected by changes in the volume of the container for

NiO(s) + CO(g) ⇌ Ni(s) + CO2(g).

BaCO3(s) ⇌ BaO(s) + CO2(g).

2CO(g) + O2(g) ⇌ 2 CO2(g).

PCl5(s) ⇌ PCl3(g) + Cl2(g).

2H2O(g) ⇌ 2H2(g) + O2(g).

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The position of equilibrium would not be appreciably affected by changes in the volume of the container for  NiO(s) + CO(g) ⇌ Ni(s) + CO2(g).

Correct Answer : Option A

Explanation:

The equilibrium position tends to change with increase or decrease in pressure or volume, or both of them. This happens because considering change in volume, when the volume of the container increases, the reactant molecule increases i.e. mole of gases and thus the position of equilibrium shifts towards the right side. Similarly in case of decreasing volume, reactant molecule decreases and the equilibrium position shifts left side.

And in case, when the mole of gases on both the sides of the equation i.e. reactant side and product side are equal, it will not have any effect on the equilibrium position on increasing or decreasing volume, or pressure.

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