A student reacts steel wool with oxygen by touching the fibers with a 9 volt battery. They begin
with 7.93 g Fe and measure the mass of the final product at 9.50 g.
The balanced equation for the reaction is:
2 Fe + 02 --> 2 FeO
A) The student claims that the percent yield of the reaction was 93.1 %. Support or reject their
claim including a calculation of percent yield as part of your evidence.

Explanation:

1. Chemical balanced equation (given)

2. Mole ratio

3. Atomic and molar masses

4. Theoretical yield

As per the theoretical mol ratio, the number of moles of FeO are equal to the number of moles of iron, thus 0.142 mol of FeO is the maximum that could be produced.

5. Percent yield, %

% = (actual yield / theoretical yield) × 100 = (7.93g / 10.2g) × 100 = 77.7%

Hence, the percent yield is 77.7%, much lower than the 93.1% claimed by the student.

i think its 5049.

i hope this !