A 155.0 −L helium tank contains pure helium at a pressure of 1835 psi and a temperature of 298 K. How many 3.5−L helium balloons can be filled from the helium in the tank? (Assume an atmospheric pressure of 1.0 atm and a temperature of 298 K.)

5528 balloons

Explanation:

Explanation:

At constant pressure and number of moles, using Boyle's law  

Given ,  

V₁ = 155.0 L  

V₂ = ?

P₁ = 1835 psi

P₂ = 1 atm  = 14.7 psia

Using above equation as:

Volume of each balloon = 3.5 L

Thus, number of balloons,

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.