2 AgNO3(aq) + CuCl2(aq) ––> Cu(NO3)2(aq) + 2 AgCl(s)
Given the above reaction equation, if 0.50 moles of AgNO3 and 0.50 moles of CuCl2 react together to form AgCl, which reactant is the limiting reagent?

AgNO3

Explanation:

Considering the equation:

2 AgNO3(aq) + CuCl2(aq) ––> Cu(NO3)2(aq) + 2 AgCl(s)

2 moles of AgNO3 reacted with 1 mole of CuCl2

divide the moles by two

1 mole of AgNO3 will react with 0.5 mole of CuCl2

then

0.5 mole AgNO3 will react with 0.25 mole of CuCl2 and limiting reagent is the reagent that is consumed when the reaction is completed.

Going by the calculation above the limiting reagent is AgNO3

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j