Methanol has the formula CH₃OH and can be produced by the reaction of carbon monoxide with hydrogen gas.
CO + 2 H₂ ? CH₃OH + heat
Using the above chemical reaction, determine how each of the following actions would affect the equilibrium of the system.
a. heating the mixture
b. adding an excess of carbon monoxide
c. removing the methanol as it is formed
d. adding a substance that reacts with carbon monoxide

Answer in explanation

Explanation:

A. Heating the mixture

Before we can explain the effect of a temperature increase, we need to know the type of reaction it is on temperature basis. As heat is produced, this type of reaction is an exothermic reaction. An exothermic reaction is one in which heat is released into the environment. As such, increasing the temperature of an exothermic reaction leads to more reactants being formed. The equilibrium will thus favor the backward reaction

B. Adding an excess of carbon monoxide

This means we are adding more reactants to the mix. This causes an increase in the available reactants necessary for the reaction to take place making it possible for more product to be formed. This thus favors the forward reaction

C. Removing the methanol as it is formed also favors the forward reaction. This favors the forward reaction as there is allocation for more product to be formed

D. Adding a substance that reacts with carbon ii oxide means less reactant availability which makes it possible for the equilibrium to favor the backward reaction as less reactant is available to give more product.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"