If a test tube contains equal concentrations of Ba2+, Pb2+, Cu2+ and Na+, describe how the ions might be separated from one another by "selectively" precipitating one at a time by adding the appropriate negative ions in the correct order. You can filter each precipitate between each reaction. Which positive ion will remain unprecipitated in the solution at the end?

2b2t

explanation:

2b2t

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole