A 0.15 mol sample of H2S is placed in a 10 L reaction vessel and heated to 1132◦C. At equilibrium, 0.03 mol H2is present. Calculate the value of Kc for the reaction2 H2S(g)⇀↽2 H2(g) + S2(g)at 1132◦C

The value of the equilibrium constant is 0.00009.

Explanation:

Initial moles of   = 0.15 mole

Volume of container = 10 L

Initial concentration of  

Moles of at equilibrium= 0.03 mole

equilibrium concentration of [/tex]

The given balanced equilibrium reaction is,

Initial conc.           0.015 M                     0     0

 At eqm. conc.    (0.015-2x) M           (2x) M   (x) M

The expression for equilibrium constant for this reaction will be,

we are given : 2x= 0.003 M

x= 0.0015 M

Now put all the given values in this expression, we get :

Thus the value of the equilibrium constant is 0.00009.