Calculate the theoretical yield of benzoin assuming you begin with 13.7 mL of benzaldehyde and assuming that the density of benzaldehyde is 1.045 g/mL.

theoretical yield of benzoin = 14.31g

Explanation:

2C7H6O => C14H12O2

molar mass of

benzaldehyde = 106g/mol

benzoin = 212g/mol

we start by calculating the mass of benzaldehyde (C7H6O):

mass of C7H6O = density x volume = 1.045x13.7 = 14.32g

number of moles of benzaldehyde= mass of benzaldehyde/ molar mass benzaldehyde.

number of moles of benzaldehyde = 14.32/106 = 0.135moles

Since benzaldehyde is the limiting reagent,

from the above equation,

2 moles of benzaldehyde produced 1 mole of benzoin

therefore, 0.135moles of of benzaldehyde will produce 0.135/2 = 0.0675 moles

mass of benzoin = number of moles of benzoin x molar mass benzoin = 0.0675 x 212 =14.31g

2b2t

explanation:

2b2t

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.