A mixture of 18 % 18% disinfectant solution is to be made from 16 % 16% and 23 % 23% disinfectant solutions. How much of each solution should be used if 28 28 gallons of the 18 % 18% solution are needed?

20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

Explanation:

According to the dilution law,

where,

= concentration of ist disinfectant solution = 16 %

= volume of pure acid solution = x gallons

= concentration of another disinfectant solution= 23%

= volume of another acid solution= (28-x) gallons

= concentration of resulting disinfectant solution = 18 %

= volume of resulting acid solution = 28 gallons

(28-x) = (28-20) = 8 gallons

Thus 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b