A gas occupies a volume of 8.60 L at 45C and 764 torr. What pressure would it occupy if the volume is adjusted to 13.3 L at 20C?

455 Torr

Explanation:

To get the correct answer, we employ the use of the General gas equation.

In its general form, the General gas equation can be written as:

P1V1/T1 = P2V2/T2

Defining the parameters;

P1 = 764 torr

V1 = 8.6L

T1 = 45 degrees Celsius = 273.15+ 45 = 318.15K

P2 = ?

V2 = 13.3L

T2 = 20 degrees Celsius = 273.15 + 20 = 293.15K

Rearranging the equation yields: P2 = P1V1T2/T1V2

Substituting the values:

P2 = (764 * 8.6 * 293.15)/(318.15 * 13.3)

P2= 455.2 Torr