What volume of hydrogen gas is required to react with 113 liters of ethylene (c2h4) according to the following reaction? (all gases are at the same temperature and pressure.) hydrogen (g) + ethylene (c2h4) (g) ethane (c2h6) (g)

The volume of hydrogen gas required for the given amount of ethylene gas is 113 L

Explanation:

At STP:

1 mole of a gas occupies 22.4 L of volume

We are given:

Volume of ethylene = 113 L

For the given chemical equation:

By Stoichiometry of the reaction:

of ethylene reacts with of hydrogen gas

So, 113 L of ethylene gas will react with = of hydrogen gas

Hence, the volume of hydrogen gas required for the given amount of ethylene gas is 113 L

the first point, i am pretty sure.

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

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