Achemist prepares a solution of sodium nitrate (nano3) by measuring out 122.g of sodium nitrate into 250.ml volumetric flask and filling the flask to the mark with water. calculate the concentration in mol/l of the chemist's sodium nitrate solution. round your answer to 3 significant digits.

The concentration of the sodium nitrate solution has been 5.72 mol/L.

The concentration has been defined as the proportion of the solute to the solvent. The concentration with presence of 1 mole of solute in a liter of solution has been given by molarity.

The molarity of the solution has been given by:

The mass of sodium nitrate in the solution has been 122 g.

The molar mass of sample has been 85 g/mol

The volume of the solution has been 250 ml.

Substituting the values for Molarity of the solution as:

The concentration of the sodium nitrate solution has been 5.72 mol/L.

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[NaNO₃] = 5.72 M

Explanation:

Molarity is a sort of concentration.

It says the moles of solute, that are contained in 1L of solution.

The volume is in mL, so let's convert to L.

250 mL . 1 L / 1000 mL = 0.250 L

Let's convert now, the mass of NaNO₃, our solute into moles

122 g / 85 g/mol = 1.43 moles

Molarity = mol / L → 1.43 mol / 0.250L = 5.72 M

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

e

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.