Asolution is formed by dissolving 36.5 g of urea, co(nh2)2, in 150.0 ml of water. what is the mole fraction of water in this solution? the density of water is 1.00 g / ml.

The mol fraction of water in this solution is 0.9319

Explanation:

Step 1: Data given

Mass of urea = 36.5 grams

Volume water = 150.0 mL

Density of water = 1.00 g/mL

Step 2: Calculate mass of water

Mass water = density * volume

Mass water = 1.00 g/mL * 150.0 mL

Mass water = 150.0 grams

Step 3: Calculate moles of water

Moles H2O = mass H2O/molar mass H2O

Moles H2O = 150.0 grams / 18.02 g/mol

Moles H2O = 8.324 moles

Step 4: Calculate moles urea

moles urea = mass urea / molar mass urea

Moles urea = 36.5 grams / 60.06 g/mol

Moles urea = 0.608 moles

Step 5: Calculate total moles

Total moles = 8.324 moles + 0.608 moles

Total moles = 8.932 moles

Step 6: Calculate mol fraction

Mol fraction of water = moles H2O / total moles

Mol fraction H2O = 8.324 moles/ 8.932 moles

Mol fraction H2O = 0.9319

The mol fraction of water in this solution is 0.9319

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.