What is the percent yield if 4.65 grams of copper is produced when 1.897 grams of aluminum reacts with an excess of copper (ii) sulfate?
2al + 3cuso4 (aq) —> al2(so4)3 (aq) + 3cu

The percentage yield if 4.65 g of copper is produced will be 70.4 %.

Explanation:

The balanced equation is given as

                  2Al + 3CuSO4 > Al2(SO4)3 + 3Cu

1.87 g of Al =  0.0693 moles of Al *  3 moles of Cu / 2 moles of Al

                  = 0.10396 moles of Cu.

This corresponds to 6.606 g of Cu which refers to theoretical yield.

% yield = (actual / theoretical) * 100

            = (4.65 / 6.606) * 100

% yield = 70.4 %.  

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be