The ph of a 1.4m solution of acetic acid (hch3co2) is measured to be 2.30. calculate the acid dissociation constant of acetic acid. round your answer to significant digits.

Ka = 1.8 × 10⁻⁵

Explanation:

Acetic acid is a weak acid that dissociates according to the following equation.

HCH₃CO₂(aq) ⇄ CH₃CO₂⁻(aq) + H⁺(aq)

The concentration of the acid is Ca = 1.4 M.

The pH is 2.30. The concentration of H⁺ is:

pH = -log [H⁺]

[H⁺] = anti log (-pH) = anti log (-2.30) = 5.01 × 10⁻³ M

We can find the acid dissociation constant (Ka) using the following expression.

[H⁺] = √(Ca × Ka)

Ka = [H⁺]²/Ca

Ka = (5.01 × 10⁻³)²/1.4

Ka = 1.8 × 10⁻⁵

water is used to store them because it would keep the radiation from getting out in the open and causing harm to the workers

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j