ch4(g)+ 2 o2(g) + co2(g) + 2 h20 (l)
calculate the ∆h° for the reaction round your answer to the correct number of decimal places based on the table values.

∆H° reaction = -890.3 kJ

Explanation:

The given equation is :

Now ,

O2 is in the standard state so its  ∆H° is zero.

∆H° is calculated by considering the formation of CO2 , H2O and CH4 .

..........∆H°a = -393.5 kJ

.....∆H°b = -285.8 kJ

..........∆H°c = -74.8 kJ

Multiply equation of water H2O by 2

and reverse the direction of equation of CH4

Hence the sign of ∆H°c = +74.8 kJ becomes +ve.

We are doing this because CH4 is to be in the reactant side not  in the product side.

∆H° reaction = ∆H°a +2(∆H°b) -∆H°c

∆H° reaction = -393.5 - 2(285.8) + 74.8

∆H° reaction = -890.3 kJ

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.

answer; talc and gypsum;