By titration, 15.0 ml of 0.1008 m sodium hydroxide is needed to neutralize a 0.2053-g sample of an organic acid. what is the molar mass of the acid if it is monopro-tic

The molar mass of monoprotic acid is 135.9 g/mol

Explanation:

To calculate the number of moles for given molarity, we use the equation:

Molarity of NaOH solution = 0.1008 M

Volume of solution = 15.0 mL

Putting values in above equation, we get:

As, the acid is monoprotic, it contains 1 hydrogen ion

1 mole of ion of NaOH neutralizes 1 mole of ion of monoprotic acid

So, 0.00151 moles of ion of NaOH will neutralize of ion of monoprotic acid

Moles of monoprotic acid = 0.00151 moles

To calculate the number of moles, we use the equation:

Moles of monoprotic acid = 0.00151 mole

Given mass of monoprotic acid = 0.2053 g

Putting values in above equation, we get:

Hence, the molar mass of monoprotic acid is 135.9 g/mol

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