How many molecules are there in 4.00 moles c3h6o3?

i need

2.408 x 10^24molecules

Explanation:

no. of moles, n=4

avogadro's constant= 6.02 x 10^23

no. of molecules, N = ?

using

N=n x l

N= 4 x 6.02 x 10^23

N = 2.408 x 10^24molecules

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles