A0.43g sample of potassium hydrogen phthalate required 24.11cm³ naoh for neutralization. calculate the molarity of the naoh

Answer

The mole ratio is 1:1

The molar mass of potassium hydrogen phthalate (C8H5KO4) is 204.22g/mol

The mass of C8H5KO4 is 0.43g

The no of moles of C8H5KO4 = mass/molar mass

No of Moles of C8H5KO4 = 0.000210557242mol

From Mole ratio the no of mole of NaOH that reacted with C8H5KO4 0.000210557242

Therefore, molaroty of NaOH is mole of NaOH/the Volume in L

Molaroty if NaOH = 0.000210557242/0.02411 = 0.08733M

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.