A0.43g sample of potassium hydrogen phthalate required 24.11cm³ naoh for neutralization. calculate the molarity of the naoh

Molarity = 0.08 M

Explanation:

Given data:

Volume of NaOH = 24.11 cm³ (24.11/1000 = 0.0241 L)

Mass of C₈H₅KO₄ = 0.43 g

Molarity of NaOH = ?

Solution:

First of all we will write the chemical equation:

C₈H₅KO₄ + NaOH  →  H₂O + KNaC₈H₄O₄

Number of moles of C₈H₅KO₄:

Number of moles  = mass/ molar mass

Number of moles = 0.43 g / 204.22 g/mol

Number of moles = 0.002 mol

Now we will compare the moles of C₈H₅KO₄ with NaOH.

                         C₈H₅KO₄          ;            NaOH

                               1                  :              1

                         0.002               :        0.002

Molarity of NaOH:

Molarity = number of moles / volume in litter

Molarity = 0.002 mol /0.0241 L

Molarity = 0.08 M

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."